Calculate the total amount of heat absorbed (in kJ) when 2.00 mol of ice at -30.0°C is converted to steam at 140.0°C. (Cp(ice)=2.06 J/g∘C; Cp(water)=4.18 J/g∘C; Cp(steam)=1.87 J/g∘C) (7 pts: Given-1point; Formula-1point; Substitution-1point; Solution-2 points; Final Answer-2points)
2 answers
See your other problem. Post your work if you need further help.
I need help
2 answers