g = 9.8/6 = 1.633333 m/s^2 on moon.
d = o.5g*t^2 = 50 m.
0.5*1.63333*t^2 = 50
0.81666t^2 = 50
t^2 = 61.22
t = 7.82 s.
Calculate the time required for an astronaut to
free-fall 50 m on the Moon.
Please show and explain steps answer is 7.9s
1 answer