Calculate the theoretical yield of ethyl acetate formed if 10 mL of ethyl alcohol (density = 0.79 ... (density = 0.79 G/mL; MW = 46.1 G/mol ) And 12 ML Of 17.4 M Acetic Acid Were Used .

Answer 1

g C2H5OH = volume x density = 10 mL x 0.79g/mL = 7.9 g.
mols C2H5OH = g/molar mass = 7.9/46.1 = approx 0.17(estimate)
g CH3COOH = volume x density = 012 mL x 17.4 M = approx 210 g (estimate)
mols CH3COOH = 209/60 = approx 3.5 (estimated)
You must go through and recalculate ALL estimates (those above AND below)
This is a limiting reagent (LR) problem.
........CH3COOH + C2H5OH ==> CH3COOC2H5 + H2O
I.........3.5.................0.17...................0........................0
So C2H5OH is the LR and 0.17 mols ethyl acetate will be formed.
Theoretical yield is 0.17 mol x molar mass ethyl acetate = ? Check all my work. Post your work if you get stuck.