I did this for you yesterday, in detail.
KHP + NaOH ==> KNaP + H2O
mols KHP = grams/molar mass = 0.8/molar mass KHP = approx 0.0039 but you need to do this step as all that follow more accurately as I've estimated.
Step 2. Convert mols KHP to mols NaOH using the coefficients in the balanced equation. That's approx 0.0039 x (1 mol NaOH/1 mol KHP) = 0.0039 x 1 = approx 0.0030
Step 3. Then M NaOH = mols NaOH/L NaOH.
You know M NaOH from the problem as 0.1000M and you know mols NaOH from step 2, substitute and solve for L NaOH.
Convert to mL if desired.
NOTE. If you already have the answer and are having trouble, the EASY way to solve your problem is to post your work and let us find the error. Telling us you can't get the units or whatever is like fishing in the dark. It's a hit and miss for us. Also, I suggest you type the problem as is; e.g. if that is 0.8g KHP or 0.8000 g KHP make sure it is correct.
Calculate the theoretical amounts of 0.1000 M NaOH titrant used to titrate 0.8 and 0.9 g KHP
Please show step by step solution , i need the correct significant figures and units to finish up the rest of the lab correctly i found the answer but for some reason ,using my answers taking me to wrong solution at the end of the lab ?
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Step 3. Its easier to just directly divide the found moles of NaOH from your initial concentration (0.1000 M NaOH). The final answer with correct SF is = 0.04 L or 40 mL
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