Calculate the surface area of the square pyramid that has a base length of 12 and a slant height of 18. Show your work. please help me guys. I need a real person to do it, and please... keep it under 3 sentences.
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The surface area of a square pyramid is equal to the sum of the areas of the base and the four triangular faces. The area of the base is 12^2 = 144, and the area of each triangular face is (1/2) * base * height = (1/2) * 12 * 18 = 108. So the total surface area is 144 + 4(108) = 576.
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