calculate the specific heat capacity of the materials for which the heat supply, mass, and temperature rises are given below:

Question

i)25200J, 0.3Kg
ii)8000J, 500g, from 20'C to 60'C
iii)9450J, 150g, from 15'C to 45'C

Answer 1

no delta Temp on i
on ii: C=8000/(500*40) in J/gC