Calculate the solute potential of a 0.20 M NaCl solution at 25° C. Remember from chemistry that NaCl breaks into two ions when it dissolves in water. Remember to convert all Celsius temperatures to Kelvin, simply by adding 273.

Answer 1

To calculate the solute potential of a 0.20 M NaCl solution at 25°C, we need to use the formula:

Ψs = -iCRT

Where:
Ψs = solute potential
i = ionization constant (for NaCl, i = 2 because it breaks into two ions)
C = molar concentration of the solution
R = ideal gas constant (0.0831 L·bar/mol·K)
T = temperature in Kelvin (25°C + 273 = 298 K)

Substituting the given values into the formula, we get:

Ψs = -2 x 0.20 x 0.0831 x 298

Now we can calculate the solute potential:

Ψs = -0.9889 bar

Therefore, the solute potential of a 0.20 M NaCl solution at 25°C is -0.9889 bar.