It most certainly does. I worked it and it produced exactly that number. If you will post your work I will find the error but I expect I can tell you without looking at your work.
You probably wrote (0.1)(2x). It should be (0.1)(2x)^2 and x = 4.44E-5M big as life.
calculate the solubility of SrF2 (ksp=7.9E-10) in 0.100 M Sr(NO3)2 ?
The answer is 4.44E-5 M how do you get that?
I Have no clue
I saw the setup but it doesnt get 4.44E-5 M
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