To calculate the relative molecular mass of NaNO3, we need to find the sum of the atomic masses of its constituent atoms.
The atomic mass of Na (Sodium) is 22.99 g/mol.
The atomic mass of N (Nitrogen) is 14.01 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
Since there is 1 Na, 1 N, and 3 O atoms in NaNO3, we can calculate the relative molecular mass as follows:
(1 x 22.99) + (1 x 14.01) + (3 x 16.00) = 22.99 + 14.01 + 48.00 = 85.00 g/mol
Therefore, the relative molecular mass of NaNO3 is 85.00 g/mol.
Calculate the relative molecular mass of
NaNO3
5 answers
Calculate the relative molecular mass of CuSO4.5H20
To calculate the relative molecular mass of CuSO4·5H2O, we need to find the sum of the atomic masses of all its constituent atoms.
The atomic mass of Cu (Copper) is 63.55 g/mol.
The atomic mass of S (Sulfur) is 32.06 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
The atomic mass of H (Hydrogen) is 1.01 g/mol.
Since there is 1 Cu, 1 S, 4 O, 10 H, and 2 O atoms in CuSO4·5H2O, we can calculate the relative molecular mass as follows:
(1 x 63.55) + (1 x 32.06) + (4 x 16.00) + (10 x 1.01) + (2 x 16.00) = 63.55 + 32.06 + 64.00 + 10.10 + 32.00 = 201.71 g/mol
Therefore, the relative molecular mass of CuSO4·5H2O is 201.71 g/mol.
The atomic mass of Cu (Copper) is 63.55 g/mol.
The atomic mass of S (Sulfur) is 32.06 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
The atomic mass of H (Hydrogen) is 1.01 g/mol.
Since there is 1 Cu, 1 S, 4 O, 10 H, and 2 O atoms in CuSO4·5H2O, we can calculate the relative molecular mass as follows:
(1 x 63.55) + (1 x 32.06) + (4 x 16.00) + (10 x 1.01) + (2 x 16.00) = 63.55 + 32.06 + 64.00 + 10.10 + 32.00 = 201.71 g/mol
Therefore, the relative molecular mass of CuSO4·5H2O is 201.71 g/mol.
Calculate the relative molecular mass of Pb(NO3)2
To calculate the relative molecular mass of Pb(NO3)2, we need to find the sum of the atomic masses of all its constituent atoms.
The atomic mass of Pb (Lead) is 207.2 g/mol.
The atomic mass of N (Nitrogen) is 14.01 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
Since there is 1 Pb, 2 N, and 6 O atoms in Pb(NO3)2, we can calculate the relative molecular mass as follows:
(1 x 207.2) + (2 x 14.01) + (6 x 16.00) = 207.2 + 28.02 + 96.00 = 331.22 g/mol.
Therefore, the relative molecular mass of Pb(NO3)2 is 331.22 g/mol.
The atomic mass of Pb (Lead) is 207.2 g/mol.
The atomic mass of N (Nitrogen) is 14.01 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
Since there is 1 Pb, 2 N, and 6 O atoms in Pb(NO3)2, we can calculate the relative molecular mass as follows:
(1 x 207.2) + (2 x 14.01) + (6 x 16.00) = 207.2 + 28.02 + 96.00 = 331.22 g/mol.
Therefore, the relative molecular mass of Pb(NO3)2 is 331.22 g/mol.