Calculate the pressure required to compress a sample of helium gas from 69.5 L (at 0.100 atm) to 60.3 L at constant temperature. Be sure your answer has the correct number of Significant figures.

Answer 1

To calculate the pressure required to compress the helium gas, we can use Boyle's Law:

P1V1 = P2V2

Where:
P1 = initial pressure = 0.100 atm
V1 = initial volume = 69.5 L
P2 = final pressure (unknown)
V2 = final volume = 60.3 L

0.100 atm * 69.5 L = P2 * 60.3 L
6.95 atm*L = 60.3 P2
P2 = 6.95 atm * 60.3 L / L = 6.95 atm

Therefore, the pressure required to compress the helium gas to 60.3 L is 6.95 atm. The answer has two significant figures, matching the input values.