Calculate the pH when 75.20 mL of 0.114 M HCl is titrated with 0 ml of 0.108 M NaOH
3 answers
The pH at what point?
it doesn't say. That's all that is asked.
Frankly I don't know what it's asking unless by titration they mean the HCl has been exactly neutralized. If that is the case, then the pH will be 7.0 because the salt produced is NaCl and neither the cation nor the anion is hydrolyzed.
The other interpretation is that the zero mL means they want the pH of the HCl at the beginning of the titration. If that is the case you want the pH of the 0.114 M HCl. H^+ = 0.114 and pH = -log(H^+)
The other interpretation is that the zero mL means they want the pH of the HCl at the beginning of the titration. If that is the case you want the pH of the 0.114 M HCl. H^+ = 0.114 and pH = -log(H^+)
3 answers