Calculate the pH of the cathode compartment for the following reaction given Ecell = 3.01 V when [Cr3+] = 0.15 M, [Al3+] = 0.30 M, and [Cr2O72-] = 0.55 M.

Question

2 Al(s) + Cr2O72-(aq) + 14 H+(aq) → 2 Al3+(aq) + 2 Cr3+(aq) + 7 H2O(l)

Answer 1

If you will show your work I can check it.

Answer 2

-0.24925=log {h+)

Answer 3

10^-0.249 = 0.56 so from these numbers the pH = 0.56.

Answer 4

thanks