millimols H2PO4- = mL x M = approx 10
millimols HCl added = 6
......H2PO4^- + H^+ ==> H3PO4
I......10.......0........0
add............6................
C......-6......-6........6
E......4........0.........6
Substitute the E line into the HH buffer equation and solve for pH.
Post your work if you turn into trouble.
Calculate the pH of the buffer formed by mixing 50.0mL of 0.200 F NaH2PO4 with 50.0mL of 0.120 F HCl
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