Calculate the pH of each of the following strong acid solutions.
0.697 g of HClO3 in 2.97 L of solution. so i convenrted grams to moles then moles/L to get M of HCl03 then i did -log of that cocentration and put htat as the ph. did i do something wrong? i got 2.415 but it was wrong please help!
2 answers
a similar problem i am having troube with is 15.10 mL of 2.00 M HCl diluted to 0.530 L
When you don't show your work we can't know what you did wrong. Next time show your work and we can spot the problem almost immediately.
You must be pushing the wrong keys.
0.697/84.459 = ?
?/2.97 = 0.002779
and -log = 2.556
You must be pushing the wrong keys.
0.697/84.459 = ?
?/2.97 = 0.002779
and -log = 2.556
0 answers