You have two problems in one here.
First, the NaOH will neutralize part of the HF. Do that first and see how much HF is left. Then you will have a solution of NaCl, HF, and NaF. The NaCl is neutral and will not change the pH. The HF/NaF mixture is a buffered solution. Use the Henderson-Hasselbalch equation to solve for the pH. Post your work if you get stuck.
Calculate the pH of a solution that is 2.00 M HF, 1.00 M NaOH, and 0.704 M NaF. (Ka = 7.2 E -4)
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