Calculate the pH of a solution prepared by mixing 25.0 mL of 0.60 M HC2H3O2 and 15.0 mL of 0.60 M NaOH?
3 answers
duplicate post.
One is using NaOH and the other NaC2H3O2, but will I still get the same pH for both?
I apologize. I didn't see the difference at first glance. No, the answer is not the same.
The first one is a buffered solution and the pH = 4.52 but check my arithmetic.
The second one is 25 x 0.6 = 9 millimoles acetic acid.
Add 15 mL x 0.6 NaOH = 9 mmoles NaOH.
You will form 9 mmoles acetate ion and that will neutralize 9 mmoles of acetic acid leaving 15-9 = 6 mmoles acetic acid. Redo the HH equation and solve for pH.
The first one is a buffered solution and the pH = 4.52 but check my arithmetic.
The second one is 25 x 0.6 = 9 millimoles acetic acid.
Add 15 mL x 0.6 NaOH = 9 mmoles NaOH.
You will form 9 mmoles acetate ion and that will neutralize 9 mmoles of acetic acid leaving 15-9 = 6 mmoles acetic acid. Redo the HH equation and solve for pH.
3 answers