To calculate the pH of a solution of 0.005 moldm^-3 tetraoxosulphate (VI) acid (H2SO4), we first need to determine the concentration of H+ ions in the solution.
Since each mole of H2SO4 produces 2 moles of H+ ions in solution, the concentration of H+ ions in the solution is 0.005 mol dm^-3 x 2 = 0.01 mol dm^-3.
Next, we can calculate the pH of the solution using the formula:
pH = -log[H+]
pH = -log(0.01)
pH = -(-2)
pH = 2
Therefore, the pH of a solution of 0.005 moldm^-3 tetraoxosulphate (VI) acid is 2.
CALCULATE THE PH OF A SOLUTION OF 0.005moldm-³ tetraoxosulphate (VI) acid. The answer plz
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