40.0 mL x 0.14 M HBrO = 5.60 millimols
5.0 mL x 0.56 M NaOH = 2.8 mmols.
.........HBrO + NaOH ==> NaBrO + H2O
I........5.60
add.............2.80..............
C.......-2.80..-2.80.....+2.80
E........2.80....0........2.80
Use the Henderson-Hasselbalch equation with the E line above to solve for pH
Calculate the pH of a solution made by combining 40.0 ml of a 0.14 molar HBrO and 5.0 ml of 0.56 molar NaOH
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