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calculate the ph of a solution by addition of 0.1 mL of 0.5m hcl to 50.0 ml pure water.

I'm supposed to use c1v1=c2v2...
but I did 0.1/50ml=0.002....
0.002x0.5.. then -log the answer and got 3 for a ph is it right?

2 answers

yes, correct.

(0.002)0.5=

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