One example each for 0.1M HCl/NaOH added to 25 mL H2O.
The diluted HCl solution is 0.1M x (1 mL/26 mL) = (HCl)
pH = -log(HCl)
The diluted NaOH solution is 0.1M x (1 mL/26 mL) = (NaOH)
pOH = -log(NaOH).
Then pH + pOH = pKw = 14.00
Calculate the pH of a 25 mL sample of distilled water after the addition of 1 mL, 2 mL, 3 mL, 4 mL, and 5 mL of NaOH and HCL. (0.1 M HCl and NaOH)
In total, you need to show 10 calculations.
2 answers
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