calculate the pH of a 1.25 x 10^-3 M HNO3 solution

Answer 1

This is hardly organic chemistry.
(HNO3) = 1.25E-3M.
Since HNO3 is a strong acid (100% ionized), that means (HNO3) = (H^+); therefore, (H^+) = 1.25E-3 and
pH = -log(H^+) = -log(1.25E-3) = ?? The answer is approximately 3