Calculate the pH of a 0.052 NH4Cl aqueous solution

Answer 1

This is a hydrolysis equation.
NH4^+ + H2O ==> NH3 + H3O^+

Ka = (Kw/Kb) = (NH3)(H3O^+)/(NH4^+)
Set up an ICE chart, substitute, solve for H3O^+ and convert to pH.