5 mM x (250/500) = 2.5 mM = 0.0025 M
Then (H^+)(OH^-)= 1E-14 and solve for H^+; convert to pH. In pure H2O the (OH^-) is 1E-7 but that isn't enough to significantly affect the total OH^-.
Calculate the pH of 250 ml of water after mixing with 250 ml of 5mM NaOH.
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