Calculate the pH of 0.01m tetraoxosulphate(VI) acid solution

Answer 1

To calculate the pH of a 0.01M tetraoxosulphate(VI) acid solution (H2SO4), we need to consider the dissociation of the acid in water.

H2SO4 is a strong acid that dissociates completely in water to form H+ ions and SO4 2- ions. The balanced chemical equation for the dissociation of H2SO4 is:

H2SO4 -> 2H+ + SO4 2-

Since H2SO4 dissociates into 2H+ ions, the concentration of H+ ions in the solution will be 0.01M x 2 = 0.02M.

The pH of a solution is calculated using the formula:
pH = -log[H+]

Therefore, the pH of a 0.01M tetraoxosulphate(VI) acid solution is:
pH = -log(0.02) = 1.70

So, the pH of a 0.01M tetraoxosulphate(VI) acid solution is 1.70.