Where did you get a name of tetraoxosulphate(vi)? There is no such name. If you have a reference please post that. If you have friends that gave you that name please let them know that no such name exists. I presume you mean H2SO4 and sulfuric acid is an acceptable name by IUPAC. There are other acceptable names, also.
For the pH, H2SO4 has two ionizable H ions. The first one is complete. The second one has a k2. Technically, one should calculate the pH from the two with the second one using k2 = 0.012. However, for beginning courses and with a molarity of 0.005, you may consider both as being complete as follows:
.....................H2SO4 ==> 2H^+ + [SO4]^2-
I...................0.005M..........0.............0
C.................-0.005............2*0.005.....0.005
E......................0.................0.01...........0.005
The E line tells you (H^+) = 0.01
pH = - log (H^+) = -log(0.01) = -(-2) = 2
Calculate the PH of 0.005 mom/dm3 of tetraoxosulphate(vi)
4 answers
Calculate the pH of 0.005 mol/dm³ to H2SO4
H2SO4 is a strong acid with two ionizable hydrogen ions. The first ionization is complete, while the second one has a Ka value of 1.2 x 10^-2.
H2SO4 ⇌ H+ + HSO4-
The equation shows that the concentration of H+ ions is equal to the concentration of the acid when fully ionized. Therefore, in 0.005 mol/dm³ of H2SO4, the concentration of H+ ions is 0.01 mol/dm³.
pH = -log[H+]
pH = -log(0.01)
pH = 2
Therefore, the pH of 0.005 mol/dm³ of H2SO4 is 2.
H2SO4 ⇌ H+ + HSO4-
The equation shows that the concentration of H+ ions is equal to the concentration of the acid when fully ionized. Therefore, in 0.005 mol/dm³ of H2SO4, the concentration of H+ ions is 0.01 mol/dm³.
pH = -log[H+]
pH = -log(0.01)
pH = 2
Therefore, the pH of 0.005 mol/dm³ of H2SO4 is 2.
PoH of 0.005 of tetraoxosulphate vi acid
1 answer