NaOH + HClO2 ==> NaClO2 + H2O so the pH at the equivalence point is determined by the hydrolysis of NaClO2 (actually the hydrolysis of the ClO2^-. The (ClO2^-) = 0.0444M. If you don't know how to do this I can show you.
.........ClO2^- + HOH ==>HClO2 + OH^-
I........0.0444..........0........0
C.........-x..............x........x
E.......0.0444-x..........x........x
Kb for ClO2^- = (Kw/Ka for HClO2) = (x)(x)/(0.0444-x)
Solve for x = (OH^-) and convert to pH.
Calculate the pH at the equivalence point in titrating 0.100 M solutions of each of the following with 0.080 M NaOH.
chlorous acid (HClO2)
benzoic acid (C6H5COOH)
2 answers
i am confused how you got the .0444?
1 answer