calculate the pH and the pOH of an aqueous solution that is 0.035 M In HCI and 0.080 M in HBr?

2 answers

HCl is a strong acid. So is HBr. They ionize 100%. (H^+) from HCl = 0.035 moles/L. That from HBr is 0.080 moles/L. Add together to find total moles/L, then pH = -log(H^+). To find pOH, remember
pH + pOH = pKw = 14.
Chem
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