pH = -log(H^+) for a and c.
pOH = -log(OH^-), then substitute into next eqn to solve for pH.
pH + pOH = pKw = 14 for b and d.
Calculate the pH and of aqueous solutions having the fol lowing ion concentrations
a. [H^ + ]=1.0*10^ -14 M
b. [OH^ - ]=5.6*10^ -8
C. [H^ + ]=2.7*10^ -3 M
d. [OH^ - ]=0.061M
2 answers
pH = - log[H+] ... pOH = - log[OH-] ... pH + pOH = 14
use a calculator to find the logs of the given concentrations
use a calculator to find the logs of the given concentrations
3 answers