Both are strong acids.
mols HBr = M x L = ?
mols HCl = M x L = ?
Total mols = sum of the two.
M acid = total mols/total L and that is the molarity of the (H^+).
Then pH = -log(acid)
calculate the pH. A solution is formed mixing 12.0 mL of .120 M HBr with 22.0mL of .180 M HCl
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