T^2 = 4*pi^2(L/g)
T^2 = 39.48(1.8/9.8) = 7.25
T = 2.69 s.
¬Calculate the period of oscillation of a simple pendulum of length 1.8 m, with a bob of mass 2.2 kg. What assumption is made in this calculation?
(g = 9.8 m s - 2)
If the bob of this pendulum is pulled aside a horizontal distance of 20cm and
released, what will be the values of (i) the kinetic energy and (ii) the velocity of the bob at the lowest point of the swing?
1 answer
1 answer