Although the period does depend slightly upon the angular deflection in the exact solution, the formula that is usually used for the period is
P = (2 pi)*sqrt (L/g)
If L = 0.8 m, you will get a period of
1.795 seconds using that formula, withy g = 9.8 m/s^2.
Using the exact formula, the period is longer by a factor
1 + {(1/2) sin(A/2)]^2 + [(3/8)sin^2(A/2)]^2+ ...}
= (1 + 0.0366 + 0.0030 + ..}
= 1.0396 at A = 45 degrees
So the true period for that angle is
1.866 seconds
Go ahead and do the 30 degree case with the same formu;a, if you must.
The exact formula can be found in F.R.E Crossley's "Dynamics in Machines", published by Ronald Press, 1954. It can probably also be found online.
calculate the period of a pendulum if the length of the pendulum is o.8m. what is the period if the angular deflection is 30 degrees? 45 degrees?
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