To determine the percentage of copper in copper(II) nitrate (Cu(NO3)2), we need to consider the atomic masses of copper (Cu), nitrogen (N), oxygen (O), and nitrate (NO3).
The atomic mass of copper (Cu) is 63.55 g/mol.
The atomic mass of nitrogen (N) is 14.01 g/mol.
The atomic mass of oxygen (O) is 16.00 g/mol.
The molar mass of nitrate (NO3) is calculated as follows:
Nitrogen (N) has a molar mass of 14.01 g/mol, and there are three oxygen (O) atoms in nitrate (NO3), so:
Molar mass of NO3 = (14.01 g/mol) + 3 × (16.00 g/mol) = 14.01 g/mol + 48.00 g/mol = 62.01 g/mol
The molar mass of copper(II) nitrate (Cu(NO3)2) can be calculated as follows:
Copper (Cu) has a molar mass of 63.55 g/mol, and there are two nitrate (NO3) ions in copper(II) nitrate (Cu(NO3)2), so:
Molar mass of Cu(NO3)2 = (63.55 g/mol) + 2 × (62.01 g/mol) = 63.55 g/mol + 124.02 g/mol = 187.57 g/mol
To calculate the percentage of copper in copper(II) nitrate, we need to divide the molar mass of copper (Cu) by the molar mass of copper(II) nitrate (Cu(NO3)2) and multiply by 100:
Percentage of copper = (63.55 g/mol / 187.57 g/mol) × 100 = 0.339 (rounded to three decimal places) × 100 ≈ 33.9%
Therefore, the percentage of copper in copper(II) nitrate (Cu(NO3)2) is approximately 33.9%.
Calculate the percentage of copper in copper(ll) nitrate
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