Calculate the partial pressure of propane in a mixture that contains equal numbers of moles of propane (C3H8) and butane (C4H10) at 20 °C and 505 mmHg. (R=0.082 L-atm/K mol)

Answer 1

For equal number of mols of each, then
Xpropane = 0.5 and
Xbutane = 0.5.
Then partial p propane = 0.5*505