Calculate the partial pressure (in atm) of propane in a mixture that contains equal weights of propane (C3H8) and butane (C4H10) at 18°C and 746 mmHg

Question

DrBob222 · Accepted Answer

P_propane = X_propane*P_total
P_{total = 746/760 = ?atm (the problem asks for atm).

So all we need to do is to determine X_propane and plug into the above.

molar mass C3H8 = about 44

molar mass C4H10 = about 58. YOu can do all of this more accurately.

X_propane = (g/44)/[(g/44)+(g/58)]

Solve for X and substitute into the above. I get something like 420 mm (but the problem asks for atm).}