Calculate the oxidation # for each atom in the molecule below. Can you help me with the rest. Thank you!!!

Question

H H H H
/ / / /

H -- C ---C ===C ----N
..
/ /
H H

Group # # of E Oxidation #

H 1 0 1 x 7 = 7

C 4 7 -3

C 4

C 4

N 5

Answer 1

3 H atom attached to first C atom.

1 H atom to second one

There is a double bound between second C atom and third one.

The third one has one H atom.

N atom has 2 dots underneath it and attached to 2 H atoms.

Note: I tried to display the diagram but it turned out to be like above. sorry about that.

Answer 2

3 H atom attached to first C atom.

1 H atom to second C atom.

There is a double bound between second C atom and the third C atom.

The third C atom has one H atom.

N atom has 2 dots underneath it and attached to 2 H atoms.

Note: I tried to display the diagram but it turned out to be like above. sorry about that.

Answer 3

This programing recognizes one space and ignores after that.

I would assign H as +1 each for a total of +7 for H.
I would assign N a +3 for a total of +3 for N
That leaves -10 for C (to make zero for the compound which it must be) which makes EACH H -3 1/3.

Answer 4

How many for each Carbon though!

That was the part I was confused!

Another question?

If we have double bond How many electrons we will have between each Carbon atoms?

Why did you assign +3 for N???

thank you!!!