3 H atom attached to first C atom.
1 H atom to second one
There is a double bound between second C atom and third one.
The third one has one H atom.
N atom has 2 dots underneath it and attached to 2 H atoms.
Note: I tried to display the diagram but it turned out to be like above. sorry about that.
Calculate the oxidation # for each atom in the molecule below. Can you help me with the rest. Thank you!!!
H H H H
/ / / /
H -- C ---C ===C ----N
..
/ /
H H
Group # # of E Oxidation #
H 1 0 1 x 7 = 7
C 4 7 -3
C 4
C 4
N 5
4 answers
3 H atom attached to first C atom.
1 H atom to second C atom.
There is a double bound between second C atom and the third C atom.
The third C atom has one H atom.
N atom has 2 dots underneath it and attached to 2 H atoms.
Note: I tried to display the diagram but it turned out to be like above. sorry about that.
1 H atom to second C atom.
There is a double bound between second C atom and the third C atom.
The third C atom has one H atom.
N atom has 2 dots underneath it and attached to 2 H atoms.
Note: I tried to display the diagram but it turned out to be like above. sorry about that.
This programing recognizes one space and ignores after that.
I would assign H as +1 each for a total of +7 for H.
I would assign N a +3 for a total of +3 for N
That leaves -10 for C (to make zero for the compound which it must be) which makes EACH H -3 1/3.
I would assign H as +1 each for a total of +7 for H.
I would assign N a +3 for a total of +3 for N
That leaves -10 for C (to make zero for the compound which it must be) which makes EACH H -3 1/3.
How many for each Carbon though!
That was the part I was confused!
Another question?
If we have double bond How many electrons we will have between each Carbon atoms?
Why did you assign +3 for N???
thank you!!!
That was the part I was confused!
Another question?
If we have double bond How many electrons we will have between each Carbon atoms?
Why did you assign +3 for N???
thank you!!!