Asked by jason
Calculate the output of a tidal barrage in mega watts if the basin is 30km2 and the tidal range is 6m.
E = PA R^2g/2
P = 1020Kg m-3
g = 9.81m-2
R = 6m
A = 30*10^6
The answer is 5.4*10^12j butwhat is this in mega watts
Thank you
jason
If you use an area of A = 30*10^6 m^2, in your formula, you will get the available energy in Joules. g = 9.81 m/s^2, NOT 9.81 m^-2. I agree with the 5.4*10^12 Joule answer. That is also 5.4*10^6 megajoules
There is no way of getting the power unless you know the period of time during which that energy is released. You have not provided the information necessary for that calculation. Perhaps the question meant to ask for Megajoules, not Megawatts.
E = PA R^2g/2
P = 1020Kg m-3
g = 9.81m-2
R = 6m
A = 30*10^6
The answer is 5.4*10^12j butwhat is this in mega watts
Thank you
jason
If you use an area of A = 30*10^6 m^2, in your formula, you will get the available energy in Joules. g = 9.81 m/s^2, NOT 9.81 m^-2. I agree with the 5.4*10^12 Joule answer. That is also 5.4*10^6 megajoules
There is no way of getting the power unless you know the period of time during which that energy is released. You have not provided the information necessary for that calculation. Perhaps the question meant to ask for Megajoules, not Megawatts.
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