Calculate the number of moles volume number of molecules of carbon dioxide liberated when 200 grams of limestone decomposed .

Answer 1

Assuming the reaction is

Ca(HCO3)2 = CACO3 + CO2 + H2O

then 200g of limestone is 200/162.11 = 1.234 moles

So, you have that many moles of CO2

1 mole occupies 22.4L at STP, and contains 6.023x10^23 molecules.

So, I guess you can now answer the questions, eh?

Answer 2

Limestone is composed mostly of calcite and aragonite which are two different crystal structures of CaCO3. Ca(HCO3)2 is soluble whereas CaCO3 is not.