calculate the number of liters of liquid ethanol (density = 0.789g/ml) required to obtain a sample containing 1.00*10^25 C2H5OH molecules

Answer 1

this is just simple dimensional analysis and conversion...

(.0 X10^23 molecules)(1 mol/6.02 X10^23 molecules)([molar mass ethanol=g/1 mol)(upside down density=mL/g)(1L/1000mL)

through this conversion process, u'll get the answer.

Answer 2

1.0*10^25 WHAT C2H5OH?