The molar mass of NO2 is 46.01 g/mol.
Using the stoichiometry of the balanced chemical equation:
2KNO3 + 10HCl → 2KCl + 2NO2 + 5Cl2 + 5H2O
We can see that 2 moles of KNO3 produce 2 moles of NO2.
Therefore, the mass of NO2 produced will be the same as the mass of KNO3 reacted.
Given that the mass of KNO3 is 5.07 g, the mass of NO2 formed will also be 5.07 g.
Therefore, the number of grams of NO2 formed is 5.07 g.
Calculate the number of grams of the product NO2 that form. Be sure your answer has the correct number of significant figures.
g NO2
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