how many moles of Fe2O3 do you have? figure that.
Then, the balanced equation tells you that you get twice that number of moles of Fe.
as your teacher did, then
300gFe2O3(1molFe2O3/159.687gFe2O3)*2moleFe/1moleFe2O3
Calculate the number of grams of Fe formed when 0.300kg of Fe2O3 reacts.
Equation:
Fe2O3+CO-->Fe+CO2
converted .300kg to 300g
Balanced Fe2O3+3CO-->2Fe+3CO2
So I started by trying this:
300gFe2O3(1molFe2O3/159.687gFe2O3)...and then I don't know where I would go from there. I'm not even sure if I'm even starting off right. I'm trying to follow along with the teacher's notes, but she didn't have anthing like this.
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Yeah, I balanced it already; I put it up. My teacher didn't do this, that's why I didn't know how to start, but is that pretty much all I have to do? That extra multiplication/division?
Just to clarify, when I convert from moles to grams, do I double Fe because it has the coefficient 2?
I got the answer (210grams). Thanks.
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