Al ==> Al^3+ + 3e
mols Al = g/atomic mass = 0.3375/27 = 0.0125
You get 3e x 0.125 = ? moles of electrons
There are 6.02E23 electrons in EACH mole of electrons.
Post your work if you get stuck.
Calculate the number of electrons produced when 0.3375g of aluminum ionizes completely.
(Al=27,L=3.0×10^23)
2 answers
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