Calculate The number of aluminium ions in 0.056g of aluminium oxide?

Answer 1

To calculate the number of aluminum ions in 0.056g of aluminum oxide, we first need to determine the molar mass of aluminum oxide.

The molar mass of aluminum oxide (Al2O3) is:
Aluminum (Al) = 26.98 g/mol
Oxygen (O) = 16.00 g/mol

Molar mass of Al2O3 = 2(Al) + 3(O) = 2(26.98) + 3(16.00) = 54.06 + 48.00 = 102.06 g/mol

Now, we can calculate the number of moles of aluminum oxide present in 0.056g:
Number of moles = Mass / Molar mass
Number of moles = 0.056g / 102.06 g/mol ≈ 0.000548 moles

Since there are 2 aluminum ions in one molecule of aluminum oxide, the number of aluminum ions present in 0.056g of aluminum oxide is:
Number of aluminum ions = 2 * 0.000548 ≈ 0.0011 moles

Therefore, there are approximately 0.0011 moles of aluminum ions in 0.056g of aluminum oxide.