you know Avogadro's Number, AN=6.023*10^23
Also, 1 mole occupies 22.4L (22400 cm^3) at STP.
(a) (50dm^3)/(22400cm^3) * AN = ?
(b) (10cm^3)/(22400cm^3) * AN * 19 = ?
(because F has 19 nucleons/atom)
Calculate the number of (a) atoms in 50 dm^3 nitrogen gas (b)nucleons in 10 cm^3 fluorine gas
4 answers
2 atoms N for every molecule N2.
1 mol occupies 22.4 dm^3; therefore,
mols F2 = 50 dm^3 x (1 mol/22.4 dm^3) = ?
# atoms = twice that.
b.Which F2? I assume F-19
Calculate mols F2 as above.
Then remember there are 19 nucleons in 1 molcule Fe.
There are two F atoms/molecule so twice that.
1 mol occupies 22.4 dm^3; therefore,
mols F2 = 50 dm^3 x (1 mol/22.4 dm^3) = ?
# atoms = twice that.
b.Which F2? I assume F-19
Calculate mols F2 as above.
Then remember there are 19 nucleons in 1 molcule Fe.
There are two F atoms/molecule so twice that.
Dang. I forgot about the molecules, not atoms.
That Fe should be F2. Sorry about that
3 answers