Calculate the no of neutrons present in 12x10^25 atoms of oxygen (8O^17)?

Answer 1

It may be 3200Na

Answer 2

1800NA

Answer 3

1800

Answer 4

In one atom of 8 O 17 nutrons are 9 so in 12×10^25 atoms number of nutrons are
9×12×10^25=1800NA

Answer 5

Since the atomic number of oxygen is =8 and atomic mass be =16yet we have given atomic mass =17. No. Of nuteron =atomic mass -atomicno. Therefore nuteron =17-8=9. Since there are 9nuteron in single atom of oxygen so12*10to the power 25atom=12*10to power 25*9=108*10to power25or1.08*10to power 27