Asked by Rishikant

Calculate the no of neutrons present in 12x10^25 atoms of oxygen (8O^17)?

Answered by yagvendra
It may be 3200Na
Answered by Vivek mishra
1800NA
Answered by Mohit sharma
1800
Answered by Anonymous
In one atom of 8 O 17 nutrons are 9 so in 12×10^25 atoms number of nutrons are
9×12×10^25=1800NA
Answered by Ritika
Since the atomic number of oxygen is =8 and atomic mass be =16yet we have given atomic mass =17. No. Of nuteron =atomic mass -atomicno. Therefore nuteron =17-8=9. Since there are 9nuteron in single atom of oxygen so12*10to the power 25atom=12*10to power 25*9=108*10to power25or1.08*10to power 27
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