calculate the momentum of a particle ,whose de Broglie's wave length is 0.1nm ?

Answer 1

λ = h/p (deBrogle Equation)
h = Plancks Constant = 6.63 x 10⁻³⁴ Joule-sec
λ = 0.10nm = 1 x 10⁻⁸ meter
p = particle momentum = h/λ = (6.63 x 10⁻³⁴ Joule-sec / 1 x 10⁻⁸ meter) = 6.63 x 10⁻²⁶ Kg·m/sec

Answer 2

λ = h/p (deBrogle Equation)
h = Plancks Constant = 6.63 x 10⁻³⁴ Joule-sec
λ = 0.10nm = 1 x 10⁻10 meter
p = particle momentum = h/λ = (6.63 x 10⁻³⁴ Joule-sec / 1 x 10⁻10 meter) = 6.63 x 10⁻²4 Kg·m/sec

Answer 3

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