Calculate the moment of Inertia for a ring with a mass 0.715 kg, an inner radius of 10.7 cm and an outer radius of 12.7 cm.

Answer 1

m•(R² + r ²)/2

Answer 2

I=0.5*M*(R^2+r^2)

I=0.5*0.715kg*[(12.7cm)^2+(10.7cm)^2]

I=98.6 kg*cm^2