Calculate the moment of Inertia for a ring with a mass 0.715 kg, an inner radius of 10.7 cm and an outer radius of 12.7 cm.
2 answers
m•(R² + r ²)/2
I=0.5*M*(R^2+r^2)
I=0.5*0.715kg*[(12.7cm)^2+(10.7cm)^2]
I=98.6 kg*cm^2
I=0.5*0.715kg*[(12.7cm)^2+(10.7cm)^2]
I=98.6 kg*cm^2