Calculate the mole fraction of fructose (molar mass = 180.2g/mol) in an aqueous solution that has a freezing point of -7.0 degrees Celsius.

Answer 1

freezing pt depression=1.86*m
m= 7/1.86=3.76
so in a kg of water, mole fraction=3.76/(1000/18+3.76) note, the denominator is total moles. 6.3 percent