Calculate the molarity of each aqueous solution with the given amount of C6H1206 (molar mass 180.15 g/mol and final volume. and final volume. Be sure each of your answer entries has the correct number of significant figures.

Question

Note: Reference the SI prefixes table for additional information.

Part 1 of 3

1.40 mol C6H1206 in 0.360 L solution

M

17.0 g C6H1206 in 5.57 L solution

M

Part 3 of 3

75.7 g C6H1206 in 270. mL solution

M

Answer 1

Part 1 of 3:

1.40 mol C6H12O6 in 0.360 L solution

Molarity (M) = moles of solute / liters of solution
M = 1.40 mol / 0.360 L

M = 3.89 M

Molarity = 3.9 M (to two significant figures)

17.0 g C6H12O6 in 5.57 L solution

First, convert grams of C6H12O6 to moles using the molar mass:
17.0 g / 180.15 g/mol = 0.0944 mol

Molarity = moles of solute / liters of solution
M = 0.0944 mol / 5.57 L

M = 0.0169 M

Molarity = 0.017 M (to two significant figures)

Part 3 of 3:

75.7 g C6H12O6 in 270 mL solution

First, convert mL to L:
270 mL = 0.270 L

Now, convert grams of C6H12O6 to moles using the molar mass:
75.7 g / 180.15 g/mol = 0.420 mol

Molarity = moles of solute / liters of solution
M = 0.420 mol / 0.270 L

M = 1.56 M

Molarity = 1.6 M (to two significant figures)