Calculate the molarity of a solution containing 15 mg of CuS04 × 5H20 in 1.00 L of solution. (6 pts)

Question

MY ANSWER
15 mg = 0.015 g. And the molar mass is 249.72 g / mol. So then we do 0.015 / 249.72 x1.00 =
0 00006007 mol L.
or 6.01 x10^-5 mol I

6. Explain in words how you would prepare 1.00 L of a 15 mg L solution of CuS04 x 5H2O (5 pts)
(HELP ME WITH THIS PLEASE!)

Answer 1

Weigh 15 mg CuSO4.5H2O, transfer to a 1 L volumetric flask, add some distilled water, swirl to dissolve all of the solid, add distilled water to the mark of the volumetric flask, stopper, mix thoroughly, label, done. Your calculations are correct.

Answer 2

Thank you so much