5.20% w/w means 5.20 g Cu(NO3)2 in 100 g solution.
1. Convert 5.20g to mols. mols = grams/molar mass.
2. Convert 100 g solution to mL using density. mass = volume x density or volume = mass/density = 100g/1.48 and convert mL to L.
3. Then M = mols from step 1/L from step 2
calculate the molarity of a copper ii nitrate solution with a density of 1.48 g/ml and a percent mass by mass of 5.20 %
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